document.write( "Question 435760: The length of a rectangle is 7 inches less than 3 times the width. If the area of the rectangle is 40 square inches, find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #301563 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "The length of a rectangle is 7 inches less than 3 times the width
\n" ); document.write( "Let x and (3x-7)represent the width and length respectively
\n" ); document.write( "Question states***
\n" ); document.write( " x(3x-7) = 40in^2
\n" ); document.write( " 3x^2 -7x - 40 = 0
\n" ); document.write( "factoring
\n" ); document.write( " (3x +8)(x-5)=0 Note:SUM of the outside terms(-15x) and the inside terms(8x) = -7x
\n" ); document.write( " (3x +8)=0 |tossing out negative solution for length
\n" ); document.write( " (x-5)=0 x = 5\", the width. the length is 8\" (3*5\"-7\") \n" ); document.write( "
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