document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=45401>Question 45401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Chris is 3 years older than Beth. Seven years from now she will be twice as old as Beth was a year ago. How old is each now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30151 by </B><A HREF=/tutors/aboutme.mpl?userid=tutmath><B>tutmath(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let Beth be x years old now, Chris is therefore x + 3 years old now.<BR>\n" );
document.write( "Seven years from now, Chris will be x + 3 + 7 = x + 10 years old\r<BR>\n" );
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document.write( "Age of Beth one year ago = x - 1 (since presently she is x years old)\r<BR>\n" );
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document.write( "From the given condition we can write the equation as:\r<BR>\n" );
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document.write( "x + 10 = 2 (x - 1)\r<BR>\n" );
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document.write( "x + 10 = 2x - 2\r<BR>\n" );
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document.write( "x = 12\r<BR>\n" );
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document.write( "Beth is 12 years old and Chris is 12 + 3 = 15 years old.\r<BR>\n" );
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