document.write( "Question 435537: the area of a rectangle is 36 ft sq the perimeter is 26' whats the lenght and width \n" ); document.write( "
Algebra.Com's Answer #301503 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
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\n" ); document.write( "the area of a rectangle is 36 ft^2 the perimeter is 26'
\n" ); document.write( " 2*L + 2*W = 26' OR L = 13-W
\n" ); document.write( " W(13-W) = 36FT^2
\n" ); document.write( " W^2-13W + 36 = 0
\n" ); document.write( "FACTORING
\n" ); document.write( " (W-9)(W-4) = 0
\n" ); document.write( " (W-9)=0
\n" ); document.write( " (W-4)= 0 W=4' and L=9' \n" ); document.write( "
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