document.write( "Question 435599: if a cirlce has (-2,-3) and (6,1) as endpoints of its diameter where does the circle cross the y-axis? \n" ); document.write( "
Algebra.Com's Answer #301495 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Find the eqn of the circle:
\n" ); document.write( "The midpoint is the center, point C
\n" ); document.write( "Cx = (-2+6)/2 = 2
\n" ); document.write( "Cy = (-3+1)/2 = -1
\n" ); document.write( "Center @ (2,-1)
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\n" ); document.write( "The radius is the distance from C to either point
\n" ); document.write( "\"r%5E2+=+4%5E2+%2B+2%5E2+=+20\"
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\n" ); document.write( "\"%28x-2%29%5E2+%2B+%28y%2B1%29%5E2+=+20\" is the circle
\n" ); document.write( "It crosses the x-axis when y = 0
\n" ); document.write( "\"x%5E2+-+4x+%2B+4+%2B+1+=+20\"
\n" ); document.write( "\"x%5E2+-+4x+-+15+=+0\"
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-4x%2B-15+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-4%29%5E2-4%2A1%2A-15=76\".
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\n" ); document.write( " Discriminant d=76 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--4%2B-sqrt%28+76+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-4%29%2Bsqrt%28+76+%29%29%2F2%5C1+=+6.35889894354067\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-4%29-sqrt%28+76+%29%29%2F2%5C1+=+-2.35889894354067\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-4x%2B-15\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-4x%2B-15+=+%28x-6.35889894354067%29%2A%28x--2.35889894354067%29\"
\n" ); document.write( " Again, the answer is: 6.35889894354067, -2.35889894354067.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-4%2Ax%2B-15+%29\"

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\n" ); document.write( "x = 2 +/- sqrt(19)\r
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