document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=435617>Question 435617</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the first n terms of an arithmetic squence is given by the formula; Sn= n/2 (3n-13)=<BR>\n" );
document.write( "i) Find the sum of the first two terms<BR>\n" );
document.write( "ii) Find the sum of the first three terms<BR>\n" );
document.write( "iii) Find the first three terms of the sequence<BR>\n" );
document.write( "iv) How many terms of this sequence are required to give a sum of 85? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301461 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301461\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> iv)<BR>\n" );
document.write( " n/2(3n-13)=85<BR>\n" );
document.write( "n(3n-13)=170<BR>\n" );
document.write( "3n^2-13n-170=0<BR>\n" );
document.write( "(n-10)(3n+17)=0<BR>\n" );
document.write( "n=10<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );