document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=435512>Question 435512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We can cut a square diagonally in half to get 2 triangles. Suppose the perimeter of the square is 3cm longer than the perimeter of a resulting triangle. What is the perimeter of the square? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301459 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301459\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let s=one side of the square.<BR>\n" );
document.write( "4s=P(square)<BR>\n" );
document.write( "2s+sqrt(2)s=P(triangle) [sqrt(2)s is the hypotenuse]<BR>\n" );
document.write( "4s-3=2s+sqrt(2)s<BR>\n" );
document.write( "2s-3=sqrt(2)s<BR>\n" );
document.write( "4s^2-12s+9=2s^2<BR>\n" );
document.write( "2s^2-12s+9=0<BR>\n" );
document.write( "s=(6+3sqrt(2))/2<BR>\n" );
document.write( "4s=2(6+3sqrt(2))<BR>\n" );
document.write( "=12+6sqrt(2)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );