document.write( "Question 435486: i need help solving this problem:
\n" ); document.write( "The length of a rectangle is 3 cm more than the width. The area is 70 cm^2. Find the dimentions of the rectangle.
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Algebra.Com's Answer #301380 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle: \"L\" is \"3cm\" more than the width \"W\". \r
\n" ); document.write( "\n" ); document.write( "The area is \"A=70+cm%5E2\". \r
\n" ); document.write( "\n" ); document.write( "Find:\r
\n" ); document.write( "\n" ); document.write( "the dimentions of the rectangle\r
\n" ); document.write( "\n" ); document.write( "\"A=L%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"70cm%5E2=L%2AW\".........\"L=W%2B3cm\"..substitute in \"70+cm%5E2=L%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"70cm%5E2=%28W%2B3cm%29%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"70cm%5E2=W%5E2%2BW%2A3cm\"\r
\n" ); document.write( "\n" ); document.write( "\"W%5E2%2B3cm%2AW-70+cm%5E2=0\"..solve quadratic for \"W\" and use only positive root because \"W\" could not be negative\r
\n" ); document.write( "\n" ); document.write( "\"W+=+%28-%283cm%29+%2B-+sqrt%28+%283cm%29%5E2-4%2A1%2A%28-70+cm%5E2%29+%29%29%2F%282%2A1%29+\" \r
\n" ); document.write( "\n" ); document.write( "\"W+=+%28-3cm+%2B-+sqrt%28+9cm%5E2%2B280cm%5E2%29%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"W+=+%28-3cm+%2B-+sqrt%28+289cm%5E2%29%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"W+=+%28-3cm+%2B-+17cm%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%28-3cm+%2B+17cm%29+%29%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"W+=+14cm%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"W+=+7cm+\"......now find \"L\"\r
\n" ); document.write( "\n" ); document.write( "\"L=7cm%2B3cm\"\r
\n" ); document.write( "\n" ); document.write( "\"L=+10cm\"\r
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