document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=435409>Question 435409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me solve this word problem?\r<BR>\n" );
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document.write( "A jar of dimes and quarters contains $2.50.  There are 4 more dimes than quarters.  How many of each kind are there?\r<BR>\n" );
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document.write( "We need to have the problem solved using two equations, equation solving isn't the problem, it's getting the equations.  What I get is this:<BR>\n" );
document.write( "x=dimes y=quarters<BR>\n" );
document.write( "x+y=2.50<BR>\n" );
document.write( "y+4=x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301359 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the second equation is good\r<BR>\n" );
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document.write( "in the first equation, where you use the total value, you need to account for the value of the coins ___ .10x + .25y = 2.50 </SPAN>\n" );
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