document.write( "Question 45263: I don't understand this problem. Please help me?\r
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\n" ); document.write( "\n" ); document.write( "Complete the following statement. 6a2 – 5a + 1 = (3a – 1)( )
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Algebra.Com's Answer #30131 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"6a%5E2+-+5a+%2B+1+=+%283a+-+1%29%28+_______++%29\"\r
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\n" ); document.write( "\n" ); document.write( "In this problem, the first times first must equal \"6a%5E2\". You are given that one of the factors is 3a, so the OTHER factor must be 2a. It should look like this:\r
\n" ); document.write( "\n" ); document.write( "\"6a%5E2+-+5a+%2B+1+=+%283a+-+1%29%28+2a+_____++++++++%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now, notice that the last term on the left side is a +1. This means that the last times last on the right side must be -1 times -1. So it must be this way for the final answer:\r
\n" ); document.write( "\n" ); document.write( "\"6a%5E2+-+5a+%2B+1+=+%283a+-+1%29%28+2a-1++%29\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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