document.write( "Question 435174: A cyclist bikes at a constant speed for 25 miles. He then returns home at the same speed but takes a different route. His return trip takes one hour longer and is 30 miles. Find his speed. \n" ); document.write( "
Algebra.Com's Answer #301275 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! Let x be his speed: \n" ); document.write( "25/x+1=30/x \n" ); document.write( "Since he takes one hour longer going home. \n" ); document.write( "Multiply both sides by x: \n" ); document.write( "25+x=30 \n" ); document.write( "x=5 \n" ); document.write( "Of course, this should be obvious, Since it took him one hour to travel the 5 extra miles he needed to get home, his speed would naturally be 5mph. \n" ); document.write( " |