document.write( "Question 435200: can you sovle the system x^2=25-y^2 and xy=-12 algebarically? \n" ); document.write( "
Algebra.Com's Answer #301274 by Gogonati(855) You can put this solution on YOUR website! To solve \n" ); document.write( "\n" ); document.write( "transformations in the first equation.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We solve these systems by substitution:1) y=1-x and x(1-x)=-12 =>-x^2+x+12=0, where x=4 and x=-3.\r \n" ); document.write( "\n" ); document.write( "Plug in x=4 we get y=-3 and plug in x=-3 we get y=4 \n" ); document.write( "We got two solution: (4, -3) and (-3, 4)\r \n" ); document.write( "\n" ); document.write( "2)y=-x-1 and x(-x-1)=-12 => -x^2-x+12=0, where x=3 and x=-4 \n" ); document.write( "Plug in x=3 we get y=-4 and plug in x=-4 we get y=3 and we get two other solutions: (3, -4) and (-4, 3). Summarize the results we :\r \n" ); document.write( "\n" ); document.write( "Answer:The solution are the points: (4, -3), (-3, 4), (3, -4) and ( -4, 3). \n" ); document.write( " \n" ); document.write( " |