document.write( "Question 435039: Given the equation 3x^2-42x+6y+147=0
\n" ); document.write( "find vertex, if parabola opens (up,down,left, or right), and focus \n" ); document.write( "

Algebra.Com's Answer #301227 by Gogonati(855) $\"\"$ $\"About$

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Transform the equation $\"3x%5E2-42x%2B6y%2B147=0\"$ in the standard form,\r
\n" ); document.write( "\n" ); document.write( " $\"%28X-Xo%29%5E2=4c%28Y-Yo%29\"$ ,\r
\n" ); document.write( "\n" ); document.write( " $\"3%28x%5E2-14x%2B49%29%2B6y%2B147-3%2A49=0\"$ => $\"3%28x-7%29%5E2=-6y\"$ => $\"%28x-7%29%5E2=-2%28y-0%29\"$ \r
\n" ); document.write( "\n" ); document.write( "From the last expression of the parabola,s equation we have: the vertex is the
\n" ); document.write( "point (7, 0) and the focus will be the point: [4c=-2 => c=-1/2],(7, -1/2).\r
\n" ); document.write( "\n" ); document.write( "Done. \n" ); document.write( "

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