document.write( "Question 435084: a coffee company wishes to make a special blend of coffee by mixing coffee beans that cost $3.20 per pound with coffee beans that cost $6.20 per pound. How many pounds of each type of coffee been are needed to make 40 pounds of coffee that costs $3.95 per pound? \n" ); document.write( "
Algebra.Com's Answer #301218 by mananth(16946)\"\" \"About 
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coffee type II x lbs
\n" ); document.write( " coffee type II ------------y lbs
\n" ); document.write( "x+y= 40 .............1
\n" ); document.write( "3.2x+6.2y=158 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -6.2
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-6.2 x -6.2 y = -248
\n" ); document.write( "3.2 x 6.2 y = 158
\n" ); document.write( "Add the two equations
\n" ); document.write( "-3x=-90
\n" ); document.write( "/-3
\n" ); document.write( "x=30 lbs coffee type II
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "x+y=40
\n" ); document.write( "30+y=40
\n" ); document.write( "y=40-30
\n" ); document.write( "y=10 lbs of coffee type II
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