document.write( "Question 435084: a coffee company wishes to make a special blend of coffee by mixing coffee beans that cost $3.20 per pound with coffee beans that cost $6.20 per pound. How many pounds of each type of coffee been are needed to make 40 pounds of coffee that costs $3.95 per pound? \n" ); document.write( "
Algebra.Com's Answer #301218 by mananth(16946)![]() ![]() You can put this solution on YOUR website! coffee type II x lbs \n" ); document.write( " coffee type II ------------y lbs \n" ); document.write( "x+y= 40 .............1 \n" ); document.write( "3.2x+6.2y=158 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -6.2 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "-6.2 x -6.2 y = -248 \n" ); document.write( "3.2 x 6.2 y = 158 \n" ); document.write( "Add the two equations \n" ); document.write( "-3x=-90 \n" ); document.write( "/-3 \n" ); document.write( "x=30 lbs coffee type II \n" ); document.write( "plug value of x in (1) \n" ); document.write( "x+y=40 \n" ); document.write( "30+y=40 \n" ); document.write( "y=40-30 \n" ); document.write( "y=10 lbs of coffee type II \n" ); document.write( " \n" ); document.write( " |