document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=435096>Question 435096</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 66. The second number is twice the first and six less than the third. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301215 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301215\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number be x<BR>\n" );
document.write( "another number = 2x<BR>\n" );
document.write( "third number = 2x+6\r<BR>\n" );
document.write( "\n" );
document.write( "x+2x+2x+6 = 66<BR>\n" );
document.write( "5x+6=66<BR>\n" );
document.write( "5x=60<BR>\n" );
document.write( "x= 12<BR>\n" );
document.write( "12,24,30 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );