document.write( "Question 435053: I need help to solve this equation for x.\r
\n" ); document.write( "\n" ); document.write( "\"2%2Alog%285%29+%2B+log%282x%2B3%29=2\"\r
\n" ); document.write( "\n" ); document.write( "This is what I've tried so far. Is this correct/am I on the right track?\r
\n" ); document.write( "\n" ); document.write( "2*log[5(2x+3)]=2
\n" ); document.write( "2*log(10x+15)=2
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Algebra.Com's Answer #301194 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
I need help to solve this equation for x.\r
\n" ); document.write( "\n" ); document.write( "\"2%2Alog%285%29+%2B+log%282x%2B3%29=2\"
\n" ); document.write( "\"log%2825%29+%2B+log%282x%2B3%29+=+2\"
\n" ); document.write( "log(25*(2x+3)) = 2
\n" ); document.write( "25*(2x+3) = 100
\n" ); document.write( "50x + 75 = 100
\n" ); document.write( "x = 1/2
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\n" ); document.write( "\n" ); document.write( "This is what I've tried so far. Is this correct/am I on the right track?\r
\n" ); document.write( "\n" ); document.write( "2*log[5(2x+3)]=2 *** You multiplied 5 x 2x+3 but left out the 2.
\n" ); document.write( "2*log(10x+15)=2
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