document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=435005>Question 435005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve the equation on the interval of [0,2pie) in radians? cos^2x+cos2x= 5/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301175 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you solve the equation on the interval of [0,2pie) in radians? cos^2x+cos2x= 5/4<BR>\n" );
document.write( "..<BR>\n" );
document.write( "cos^2x+cos2x= 5/4<BR>\n" );
document.write( "2cos^2x=5/4<BR>\n" );
document.write( "cos^2x=5/8<BR>\n" );
document.write( "cosx=sqrt(5/8)=.79057<BR>\n" );
document.write( "arccos(.79057)=.65906<BR>\n" );
document.write( "x=.65906 and 5.62094 radians </SPAN>\n" );
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