document.write( "Question 434954: A banker invested a portion of $10,000 at 5% interest per year and the remainder at 4% interest per year. If the banker received $470 in interest after 1 year, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #301150 by mananth(16946)\"\" \"About 
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Part I 5.00% per annum
\n" ); document.write( "Part II 4.00% per annum
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\n" ); document.write( "x+y=10000 ------------------------1
\n" ); document.write( "5.00%x+ 4.00%y =$470.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "5x+4y=$47,000.00 --------2
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\n" ); document.write( "Multiply (1) by -5
\n" ); document.write( "we get
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\n" ); document.write( "-5x-5y =-50000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( " -y=-$3,000.00
\n" ); document.write( "y=$3,000.00 investment at 4.00%
\n" ); document.write( "Balance $7,000.00 investment at 5.00%
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