document.write( "Question 434850: Twice the square of an integer is 3 less than 7 times the integer. Find the integer.\r
\n" ); document.write( "\n" ); document.write( "2x^ = 1st integer
\n" ); document.write( "7x-3 = 2nd integer\r
\n" ); document.write( "\n" ); document.write( "2x^=7x-3\r
\n" ); document.write( "\n" ); document.write( "2x^ + 7x + 3 = 0
\n" ); document.write( "(2x+1)(x+3)
\n" ); document.write( "2x+1 = 0 x+3=0
\n" ); document.write( "2x=-1 x=-3
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\n" ); document.write( "x=-1/2 & x = -3
\n" ); document.write( "this is as far as i could get? Is this right? We are to solve this using the GSSC model.\r
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Algebra.Com's Answer #301111 by Alan3354(69443)\"\" \"About 
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Twice the square of an integer is 3 less than 7 times the integer. Find the integer.\r
\n" ); document.write( "\n" ); document.write( "2x^2 = 1st integer
\n" ); document.write( "7x-3 = 2nd integer\r
\n" ); document.write( "\n" ); document.write( "2x^2=7x-3\r
\n" ); document.write( "\n" ); document.write( "2x^2 + 7x + 3 = 0 ********** \"2x%5E2+-+7x+%2B+3+=+0\"
\n" ); document.write( "(2x-1)*(x-3) = 0
\n" ); document.write( "x = +1/2, 3 Only your signs are wrong.
\n" ); document.write( "x^ is meaningless, the exponent has to be entered. It isn't always 2.
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\n" ); document.write( "(2x+1)(x+3)
\n" ); document.write( "2x+1 = 0 x+3=0
\n" ); document.write( "2x=-1 x=-3
\n" ); document.write( "
\n" ); document.write( "x=-1/2 & x = -3
\n" ); document.write( "this is as far as i could get? Is this right? We are to solve this using the GSSC model.
\n" ); document.write( "I don't know what the GSSC model means.
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