document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=45376>Question 45376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the ordered pair solution of y = -1/3x + 4/3<BR>\n" );
document.write( "which is (-2,2) but I'm having trouble remembering how to solve.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30110 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30110\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The point (-2, 2) is just ONE ordered pair solution...there are an infinite number of them...but to verify that it is indeed a solution, merely plug -2 in for x and 2 in for y and see if the equation becomes a true statement...so we have<BR>\n" );
document.write( "2 = (-1/3)(-2) + 4/3<BR>\n" );
document.write( "2 = 2/3 + 4/3<BR>\n" );
document.write( "2 = 6/3<BR>\n" );
document.write( "2 = 2<BR>\n" );
document.write( "It checks out okay... </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );