document.write( "Question 434503: Moving company A charges $75 plus $40 an hour to move households across town. Moving Company B charges $65 an hour for cross-town moves. For what lengths of time is Moving Company B more expensive than Moving Company A? Write an inequality. \n" ); document.write( "
Algebra.Com's Answer #301004 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let x be the number of hours\r \n" ); document.write( "\n" ); document.write( "Company B = 75+40x \n" ); document.write( "Company A 65x\r \n" ); document.write( "\n" ); document.write( "Company B > Company A \r \n" ); document.write( "\n" ); document.write( "75+40x> 65x \n" ); document.write( "add -40x \n" ); document.write( "75>65x-40x \n" ); document.write( "75>25x \n" ); document.write( "75>x\r \n" ); document.write( "\n" ); document.write( "For x less than 3 hours company B is expensive. \n" ); document.write( " |