document.write( "Question 434210: The distance from Kenya's house to her job is 18 miles. One morning she left her house at 7:15 a.m. She traveled at the rate of 45 miles per hour for 20 minutes, but to traffic she had to slow down to 20 miles per hour. At what time did Kenya arrive at work? \n" ); document.write( "
Algebra.Com's Answer #301000 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The distance from Kenya's house to her job is 18 miles. \n" ); document.write( " One morning she left her house at 7:15 a.m. \n" ); document.write( " She traveled at the rate of 45 miles per hour for 20 minutes, but due to traffic \n" ); document.write( " she had to slow down to 20 miles per hour. \n" ); document.write( " At what time did Kenya arrive at work? \n" ); document.write( ": \n" ); document.write( "Find how far at 45 mph: \n" ); document.write( "20 min = \n" ); document.write( " \n" ); document.write( "therefore \n" ); document.write( "18 - 15 = 3 miles at 20 mph \n" ); document.write( "Find the time at 20 mph \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Total time: .15 + .3333 = .4833 hrs or .4833 * 60 ~ 29 min \n" ); document.write( ": \n" ); document.write( "7:15 + :29 = 7:44 a.m. arrive at work \n" ); document.write( " |