document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=427129>Question 427129</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation.\r<BR>\n" );
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document.write( "9x = 3x^3<BR>\n" );
document.write( "3x^3-9x=0{subtracted 9x from both sides}<BR>\n" );
document.write( "3x(x^2-3){factored 3x out}<BR>\n" );
document.write( "sqrt(x^2)=+-sqrt(3)  {to take away ^2}<BR>\n" );
document.write( "x=+-sqrt(3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300868 by </B><A HREF=/tutors/aboutme.mpl?userid=adrian438><B>adrian438(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=adrian438><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x^3-9x=0{subtracted 9x from both sides}<BR>\n" );
document.write( "3x(x^2-3){factored 3x out}<BR>\n" );
document.write( "sqrt(x^2)=+-sqrt(3)  {to take away ^2}<BR>\n" );
document.write( "x=+-sqrt(3)\r<BR>\n" );
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document.write( "3x=0<BR>\n" );
document.write( "x=0/3<BR>\n" );
document.write( "x=0\r<BR>\n" );
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document.write( "answer: x=0,+-sqrt(3) </SPAN>\n" );
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