document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=434156>Question 434156</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 4 less than a second number. Twice the second number is 1 less than 3 times the first. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300857 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300857\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let second number be x<BR>\n" );
document.write( "the first number = x-4\r<BR>\n" );
document.write( "\n" );
document.write( "2x =3(x-4)-1<BR>\n" );
document.write( "2x=3x-12-1<BR>\n" );
document.write( "-x=-13<BR>\n" );
document.write( "x= 13 <BR>\n" );
document.write( "The numbers are 13 & 9 </SPAN>\n" );
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