document.write( "Question 434148: John and Brian leave Williston at the same time. John drives north and Brian drives east. John's average speed is 10 miles per hour slower than Brian's. At the end of one hour they are 50 miles apart. Find Brian's average speed. \n" ); document.write( "
Algebra.Com's Answer #300854 by mananth(16949)\"\" \"About 
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John x mph
\n" ); document.write( "Brian x+ 10
\n" ); document.write( "..
\n" ); document.write( "They are going away from each other.
\n" ); document.write( "
\n" ); document.write( "So add up their speed.
\n" ); document.write( "
\n" ); document.write( "combined speed = x+x+10
\n" ); document.write( "(2x+10)
\n" ); document.write( "Time = 1 hours
\n" ); document.write( "Distance = 50 miles
\n" ); document.write( "Distance = speed * time
\n" ); document.write( "(2x+10)*1=50
\n" ); document.write( "2x+10=50
\n" ); document.write( "2x=50-10
\n" ); document.write( "2x=40
\n" ); document.write( "/2
\n" ); document.write( "x=20mph John
\n" ); document.write( "Brian 20+10=30mph
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