document.write( "Question 434121: please help me solve this problem using logarithms: \"+5%282%5EX%29+=+3+-+2%5E%28x%2B2%29+\" \n" ); document.write( "
Algebra.Com's Answer #300844 by Gogonati(855)\"\" \"About 
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To solve the equation:\"5%2A2%5Ex=3-2%5E%28x%2B2%29\", we substitute \"2%5Ex=y\" and\r
\n" ); document.write( "\n" ); document.write( "\"2%5E%28x%2B2%29=2%5E2%2A2%5Ex=4%2Ay\". Rewrite the equation: 5y=3-4y, solve this equation,\r
\n" ); document.write( "\n" ); document.write( "5y+4y=3 => 9y=3 => y=1/3. Now we find the x, since 2^x=y, substitute:\r
\n" ); document.write( "\n" ); document.write( "\"2%5Ex=1%2F3\", taking natural logarithms of each side we have:\r
\n" ); document.write( "\n" ); document.write( "\"x%2Aln2=-ln3\" => \"x=-ln3%2Fln2\".\r
\n" ); document.write( "\n" ); document.write( "Done.\r
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