document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=434074>Question 434074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the present ages of john and his father is 89 years. After 11 years the age of father will be twice the age of john at that time, find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300833 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> john's age =x<BR>\n" );
document.write( "father's age = 89-x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "after 11 years\r<BR>\n" );
document.write( "\n" );
document.write( "john's age = x+11<BR>\n" );
document.write( "father's age = 99-x<BR>\n" );
document.write( "...<BR>\n" );
document.write( "99-x=2(x+11)<BR>\n" );
document.write( "99-x=2x+22<BR>\n" );
document.write( "99-22=2x-x<BR>\n" );
document.write( "77=x fathers age<BR>\n" );
document.write( "12 = sons age </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );