document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=432922>Question 432922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> passes through the point (-1,6) and is perpendicular to the line whose equation is 4x+2y=3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300809 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300809\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the equation of the perpendicular line must be 2x - 4y = c, where c is an unknown constant.  To find c, use the coordinates of the given point:<BR>\n" );
document.write( "2*-1 -4*6 = c, or -2 - 24 = c, or c = -26.<BR>\n" );
document.write( "Hence the equation of the perpendicular line is 2x - 4y = -26, or x - 2y = -13. </SPAN>\n" );
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