document.write( "Question 433980: b/2 - a/3 = 7
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document.write( "b/5 + a/6 = 1 \n" );
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Algebra.Com's Answer #300761 by mananth(16946)![]() ![]() You can put this solution on YOUR website! b/2 - a/3 = 7 \n" ); document.write( "3b-2a =6*7 \n" ); document.write( "3b-2a=42.............1 \n" ); document.write( " \n" ); document.write( "b/5 + a/6 = 1\r \n" ); document.write( "\n" ); document.write( "6b+5a= 30*1 \n" ); document.write( "6b+5a= 30............2\r \n" ); document.write( "\n" ); document.write( "-2a+3b= 42 .............1 \n" ); document.write( "5a+6b=30 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -4 \n" ); document.write( "Multiply (2) by 2 \n" ); document.write( "8a-12b= -168 \n" ); document.write( "10a+12b=60 \n" ); document.write( "Add the two equations \n" ); document.write( "18a = -108 \n" ); document.write( "/18 \n" ); document.write( "a=-6 \n" ); document.write( "plug value of a in (1) \n" ); document.write( "-2a+3b= 42 \n" ); document.write( "12+3b=42 \n" ); document.write( "3b=42-12 \n" ); document.write( "3b=30 \n" ); document.write( "b=10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |