document.write( "Question 433980: b/2 - a/3 = 7
\n" ); document.write( "b/5 + a/6 = 1
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Algebra.Com's Answer #300761 by mananth(16946)\"\" \"About 
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b/2 - a/3 = 7
\n" ); document.write( "3b-2a =6*7
\n" ); document.write( "3b-2a=42.............1
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\n" ); document.write( "b/5 + a/6 = 1\r
\n" ); document.write( "\n" ); document.write( "6b+5a= 30*1
\n" ); document.write( "6b+5a= 30............2\r
\n" ); document.write( "\n" ); document.write( "-2a+3b= 42 .............1
\n" ); document.write( "5a+6b=30 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -4
\n" ); document.write( "Multiply (2) by 2
\n" ); document.write( "8a-12b= -168
\n" ); document.write( "10a+12b=60
\n" ); document.write( "Add the two equations
\n" ); document.write( "18a = -108
\n" ); document.write( "/18
\n" ); document.write( "a=-6
\n" ); document.write( "plug value of a in (1)
\n" ); document.write( "-2a+3b= 42
\n" ); document.write( "12+3b=42
\n" ); document.write( "3b=42-12
\n" ); document.write( "3b=30
\n" ); document.write( "b=10\r
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