document.write( "Question 45332: solve for a by completing the square:
\n" ); document.write( "a^2-10a+1=0
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Algebra.Com's Answer #30075 by tutorcecilia(2152)\"\" \"About 
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a^2-10a+1-1=0-1 [Subtract 1 from both sides]
\n" ); document.write( "a^2-10a = -1 [Simplify]
\n" ); document.write( "a^2-10a + (10/2)^2 = -1 [Divide and square the second coefficient]
\n" ); document.write( "a^2-10a + (10/2)^2 = -1 + (10/2)^2 [Add it to both sides of the equation]
\n" ); document.write( "a^2-10a + (5)^2 = -1 + (5)^2 [Simplify]
\n" ); document.write( "a^2-10a + (5)^2 = -1 + 25 [Further simplify the right hand side only]
\n" ); document.write( "a^2-10a + (5)^2 = 24 [Further simplify the right hand side of the equation only]
\n" ); document.write( "(a-5)(a-5) = 24 [Factor the polynomial]
\n" ); document.write( "\"%28%28sqrt%28a-5%29%29%5E2%29\"={{sqrt(24)}}} [Take the square root of both sides]
\n" ); document.write( "a-5 = +-2\"sqrt%286%29\" [Simplify]
\n" ); document.write( "a-5+5 = +-2\"sqrt%286%29\" +5 [Solve for \"a\"]
\n" ); document.write( "a = +-2\"sqrt%286%29\" +5
\n" ); document.write( "a = 5+-2\"sqrt%286%29\" [The two answers]
\n" ); document.write( "a = 5 + 2\"sqrt%286%29\" or 5 - 2\"sqrt%286%29\" \r
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