document.write( "Question 45332: solve for a by completing the square:
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document.write( "a^2-10a+1=0 \n" );
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Algebra.Com's Answer #30075 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! a^2-10a+1-1=0-1 [Subtract 1 from both sides] \n" ); document.write( "a^2-10a = -1 [Simplify] \n" ); document.write( "a^2-10a + (10/2)^2 = -1 [Divide and square the second coefficient] \n" ); document.write( "a^2-10a + (10/2)^2 = -1 + (10/2)^2 [Add it to both sides of the equation] \n" ); document.write( "a^2-10a + (5)^2 = -1 + (5)^2 [Simplify] \n" ); document.write( "a^2-10a + (5)^2 = -1 + 25 [Further simplify the right hand side only] \n" ); document.write( "a^2-10a + (5)^2 = 24 [Further simplify the right hand side of the equation only] \n" ); document.write( "(a-5)(a-5) = 24 [Factor the polynomial] \n" ); document.write( " \n" ); document.write( "a-5 = +-2 \n" ); document.write( "a-5+5 = +-2 \n" ); document.write( "a = +-2 \n" ); document.write( "a = 5+-2 \n" ); document.write( "a = 5 + 2 \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |