document.write( "Question 433915: you invested 7000 in two accounts paying 2% and 3% annual interest.if the total
\n" ); document.write( "interest earned for the year was 170 how much was invested at each rate \n" ); document.write( "

Algebra.Com's Answer #300724 by stanbon(75887) $\"\"$ $\"About$

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you invested 7000 in two accounts paying 2% and 3% annual interest.if the total
\n" ); document.write( "interest earned for the year was 170 how much was invested at each rate
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity: x + y = 7000
\n" ); document.write( "Interest:0.02x+0.03y = 170
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\n" ); document.write( "Multiply 1st by 2
\n" ); document.write( "Multiply 2nd by 100
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\n" ); document.write( "2x + 2y = 2*7000
\n" ); document.write( "2x + 3y = 17000
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\n" ); document.write( "Subtract and solve for \"Y\";
\n" ); document.write( "y = $3000 (amt. invested at 2%)
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\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x+y = 7000
\n" ); document.write( "x+3000 = 7000
\n" ); document.write( "x = $4000 (amt. invested at 3%)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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