document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=433814>Question 433814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Boating: A family travels 18 miles down river and returns. It takes 8 hours to make the round trip. Their rate in still water is twice the rate of the rivers current. How long will the return trip take? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300690 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the river current be x km/hr.<BR>\n" );
document.write( "Then, speed of the boat is 2x km/hr.\r<BR>\n" );
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document.write( "Time taken to go 18km downstream = 18/(2x+x) = 6/x hr.\r<BR>\n" );
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document.write( "Time taken to go 18km upstream = 18/(2x-x) = 18/x hr.\r<BR>\n" );
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document.write( "Total time taken = 6/x + 18/x hr. \r<BR>\n" );
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document.write( "6/x + 18/x = 8\r<BR>\n" );
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document.write( "24/x = 8\r<BR>\n" );
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document.write( "x = 3\r<BR>\n" );
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document.write( "Therefore, time taken for return trip (18km upstream) = 18/(2x-x) = 18/3 = 6 hr. </SPAN>\n" );
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