document.write( "Question 433708: 2r - 3s =-3\r
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document.write( "3r+2s=28\r
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document.write( "solve by the elimination method \n" );
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Algebra.Com's Answer #300663 by rwm(914)![]() ![]() ![]() You can put this solution on YOUR website! r=6 s=5 \n" ); document.write( "multiply the first by 3 and the second by 2 \n" ); document.write( "2r - 3s =-3 \n" ); document.write( "6r-9s=-9 \n" ); document.write( "3r+2s=28 \n" ); document.write( "6r+4s=56\r \n" ); document.write( "\n" ); document.write( "6r-9s=-9 \n" ); document.write( "6r+4s=56 \n" ); document.write( "subtract \n" ); document.write( "-9s-4s=-9-56 \n" ); document.write( "-13s=-65 \n" ); document.write( "s=5 \n" ); document.write( "2r-3s=-3 \n" ); document.write( "2r-3*5=-3 \n" ); document.write( "2r-15=-3 \n" ); document.write( "2r=12 \n" ); document.write( "r=6\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |