document.write( "Question 433708: 2r - 3s =-3\r
\n" ); document.write( "\n" ); document.write( "3r+2s=28\r
\n" ); document.write( "\n" ); document.write( "solve by the elimination method
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Algebra.Com's Answer #300663 by rwm(914)\"\" \"About 
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r=6 s=5
\n" ); document.write( "multiply the first by 3 and the second by 2
\n" ); document.write( "2r - 3s =-3
\n" ); document.write( "6r-9s=-9
\n" ); document.write( "3r+2s=28
\n" ); document.write( "6r+4s=56\r
\n" ); document.write( "\n" ); document.write( "6r-9s=-9
\n" ); document.write( "6r+4s=56
\n" ); document.write( "subtract
\n" ); document.write( "-9s-4s=-9-56
\n" ); document.write( "-13s=-65
\n" ); document.write( "s=5
\n" ); document.write( "2r-3s=-3
\n" ); document.write( "2r-3*5=-3
\n" ); document.write( "2r-15=-3
\n" ); document.write( "2r=12
\n" ); document.write( "r=6\r
\n" ); document.write( "\n" ); document.write( "
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