document.write( "Question 433657: You are given the equation 3a + b = 200 where a and b are positive integers. Determine the number of solutions (a,b) for the given equation.
\n" ); document.write( "HELP!!!!!!!!!!!!!!!!!
\n" ); document.write( "

Algebra.Com's Answer #300651 by psbhowmick(878)\"\" \"About 
You can put this solution on YOUR website!
\"3a+%2B+b+=+200\"
\n" ); document.write( "\"a+=+%28200+-+b%29%2F3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since \"a\" has to be a positive integer then \"200+-+b\" has to be a multiple of 3.\r
\n" ); document.write( "\n" ); document.write( "So \"200-b\" can be 3, 6, 9,...., 198.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Thus 66 solutions are possible.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "P.S.: \"a=b=0\" cannot be a solution since both \"a\" and \"b\" has to be positive.
\n" ); document.write( "
\n" );