document.write( "Question 433515: simplify the logarithm\r
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Algebra.Com's Answer #300640 by richard1234(7193)\"\" \"About 
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\"log%288%2C16%29+=+log%28a%2C+8%29%2Flog%28a%2C+16%29\" by the change of base formula. For simplicity, we can let \"a+=+2\" to obtain \"log%282%2C8%29%2Flog%282%2C16%29+=+3%2F4\". \n" ); document.write( "
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