document.write( "Question 433620: the product of the second and third of three consecutive integers is 2 more than 7 times the first integer \n" ); document.write( "
Algebra.Com's Answer #300591 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "Let's have x be the first integer and x+1 and x+2 be the next 2 integers. Now we can set up the equation as:
\n" ); document.write( "(x+1)(x+2)=7x+2
\n" ); document.write( "Expand this out:
\n" ); document.write( "x^2+3x+2=7x+2
\n" ); document.write( "Subtract 7x and 2 to get:
\n" ); document.write( "x^2-4x=0
\n" ); document.write( "factor this out to get:
\n" ); document.write( "x(x-4)=0
\n" ); document.write( "Solve for x and we get:
\n" ); document.write( "x=0
\n" ); document.write( "x=4
\n" ); document.write( "So we can see that 0,1,2 and
\n" ); document.write( "4,5,6 work as answers.
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com
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