document.write( "Question 433620: the product of the second and third of three consecutive integers is 2 more than 7 times the first integer \n" ); document.write( "
Algebra.Com's Answer #300591 by unlockmath(1688)![]() ![]() You can put this solution on YOUR website! Hello, \n" ); document.write( "Let's have x be the first integer and x+1 and x+2 be the next 2 integers. Now we can set up the equation as: \n" ); document.write( "(x+1)(x+2)=7x+2 \n" ); document.write( "Expand this out: \n" ); document.write( "x^2+3x+2=7x+2 \n" ); document.write( "Subtract 7x and 2 to get: \n" ); document.write( "x^2-4x=0 \n" ); document.write( "factor this out to get: \n" ); document.write( "x(x-4)=0 \n" ); document.write( "Solve for x and we get: \n" ); document.write( "x=0 \n" ); document.write( "x=4 \n" ); document.write( "So we can see that 0,1,2 and \n" ); document.write( "4,5,6 work as answers. \n" ); document.write( "Make sense? \n" ); document.write( "RJ \n" ); document.write( "www.math-unlock.com \n" ); document.write( " |