document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=433610>Question 433610</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of a 25% acid solution must be mixed with 100 gallons of a 6% acid solution to obtain a mixture that is 20% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300581 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  how many gallons of a 25% acid solution must be mixed with 100 gallons of a 6% acid solution to obtain a mixture that is 20% acid?<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
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document.write( "0.25x + 0.06*100 = 0.20(x+100)<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "25x + 6*100 = 20x+20*100<BR>\n" );
document.write( "5x = 14*100<BR>\n" );
document.write( "x = 14*20<BR>\n" );
document.write( "x = 280 gallons (amt of 25% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );