document.write( "Question 45318: find the equation of the line that passes through (-2,3) and (4,-1).
\n" ); document.write( "the formula I believe is y-y1 = y2-y1/x2-x1 (x-x1)
\n" ); document.write( "I'm not quite sure as to how to set that up. do I solve as I go?
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Algebra.Com's Answer #30058 by tutorcecilia(2152)\"\" \"About 
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First, I would find the slope of the line:
\n" ); document.write( "m = (y2-y1)/(x2-x1) = (-1-3)/4-(-2) = -4/6 = -2/3
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\n" ); document.write( "Use the slope-intercept formula (y=mx+b) to find the y-intercept(b).
\n" ); document.write( "Pick point (-2, 3) and plug-in the values:
\n" ); document.write( "(3)=(-2/3)(-2)+ b
\n" ); document.write( "3 = 4/3 + b
\n" ); document.write( "3 - 4/3 = 4/3 - 4/3 + b
\n" ); document.write( "(9-4)/3 = b
\n" ); document.write( "b = 5/3
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\n" ); document.write( "Plug the slope (m) and the y=intercept (b) into the formula y-mx+b:
\n" ); document.write( "y=(-2/3)x + 5/3
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\n" ); document.write( "Check the formula by plugging in one of the given points. Pick point (4, -1):
\n" ); document.write( "(-1)=(-2/3)(4)+ 5/3
\n" ); document.write( "-1=-3/3
\n" ); document.write( "-1=-1 Checks out.\r
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