document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=433583>Question 433583</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman earns $1,240 in interest from two accounts in a year. If she has three times as much invested at 9% as she does at 4%, how much does she have in each account?\r<BR>\n" );
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document.write( "x at 4%<BR>\n" );
document.write( "y at 9% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300554 by </B><A HREF=/tutors/aboutme.mpl?userid=belle3833><B>belle3833(46)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=belle3833><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=belle3833><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300554\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.09y+0.04x=1240\r<BR>\n" );
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document.write( "3x=y (this is because she has three times the amount at 9%. So 3 x the amount at 4% = the amount at 9%)<BR>\n" );
document.write( "substitue this into the first equation<BR>\n" );
document.write( "0.09(3x)+0.04x=1240\r<BR>\n" );
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document.write( "0.27x+0.04x=1240<BR>\n" );
document.write( "0.31x=1240\r<BR>\n" );
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document.write( "x=1240/0.31<BR>\n" );
document.write( "x=4000<BR>\n" );
document.write( "so she has $4000 at 4% and 12000 at 9%\r<BR>\n" );
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document.write( "hope this helps\r<BR>\n" );
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document.write( " </SPAN>\n" );
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