document.write( "Question 433555: verify the idenity
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Algebra.Com's Answer #300546 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
\"Sec%5E4x+-+Sec%5E2x+=+Tan%5E4x+%2B+Tan%5E2x\"
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document.write( "To do this one we need the identity \r\n" );
document.write( "\"1%2BTan%5E2theta=Sec%5E2theta\" and its rearranged version \"Sec%5E2theta-1=Tan%5E2theta\"\r\n" );
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document.write( "\"Sec%5E4x+-+Sec%5E2x+=+Tan%5E4x+%2B+Tan%5E2x\"\r\n" );
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document.write( "Factor common factor \"Sec%5E2x\" out of the left side\r\n" );
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document.write( "\"Sec%5E2x%28Sec%5E2x-1%29+=+Tan%5E4x+%2B+Tan%5E2x\"\r\n" );
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document.write( "Replace the first factor on the left, \"Sec%5E2x\", by \"1%2BTan%5Ex\"\r\n" );
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document.write( "Replace the second factor on the left, \"%28Sec%5E2-1%29\" by \"Tan%5E2x\"\r\n" );
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document.write( "\"%281%2BTan%5E2x%29%28Tan%5E2x%29+=+Tan%5E4x+%2B+Tan%5E2x\"\r\n" );
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document.write( "Multiply the left side out:\r\n" );
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document.write( "\"Tan%5E2x+%2B+Tan%5E4x+=Tan%5E4x+%2B+Tan%5E2x\"\r\n" );
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document.write( "Reverse the terms on the left\r\n" );
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document.write( "\"Tan%5E4x+%2B+Tan%5E2x+=Tan%5E4x+%2B+Tan%5E2x\"\r\n" );
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document.write( "Edwin

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