document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=45262>Question 45262</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a hard time with this, can someone help me please?\r<BR>\n" );
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document.write( "Rewrite the middle term as the sum of two terms and then factor completely.	15x2 – 21x + 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30054 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15x2 – 21x + 6\r<BR>\n" );
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document.write( "This is called the \"ac\" method of factoring.<BR>\n" );
document.write( "You want to find two numbers whose product is ac=(15)(6)=90<BR>\n" );
document.write( "and whose sum is b=-21\r<BR>\n" );
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document.write( "The numbers are -15 and -6.<BR>\n" );
document.write( "Rewrite the problem using -15x -6x in place of -21x, as follows:<BR>\n" );
document.write( "15x^2-15x-6x+6\r<BR>\n" );
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document.write( "Now factor by grouping as follows:\r<BR>\n" );
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document.write( "15x(x-1)-6(x-1)<BR>\n" );
document.write( "(x-1)(15x-6)\r<BR>\n" );
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document.write( "That's it.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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