document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=433508>Question 433508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me:\r<BR>\n" );
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document.write( "A satellite dish shaped like a parabola is 12 feet across and 4 feet deep. How high above the base dish should the receiver be placed if it is located at the focus of the parabola? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #300539 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=300539\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> picture the parabolic cross-section starting at the origin and extending along the x-axis\r<BR>\n" );
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document.write( "the vertex (bottom of the dish) is (6,-4); and the roots are 0 and 12\r<BR>\n" );
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document.write( "using the vertex form ___ y = a(x - 6) - 4\r<BR>\n" );
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document.write( "0 = a(0 - 6)^2 - 4\r<BR>\n" );
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document.write( "4 = 36a ___ a = 1/9\r<BR>\n" );
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document.write( "a = 1 / 4p ___where p is the distance from the vertex to the focus\r<BR>\n" );
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document.write( "p = 1 / 4a ___ in this case ___ p = 9/4\r<BR>\n" );
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document.write( "so the receiver is 9/4 feet above the bottom of the dish </SPAN>\n" );
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