document.write( "Question 433559: verify the question
\n" ); document.write( "sec^2x-csc^2x=(tanx-cotx)/(sinx*cosx)
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Algebra.Com's Answer #300535 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
use these identities:\r
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\n" ); document.write( "\n" ); document.write( "tan^2x+1 = sec^2x)\r
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\n" ); document.write( "\n" ); document.write( "1 + cot^2x = csc^2x\r
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\n" ); document.write( "\n" ); document.write( "prove that left side is equal to right side:\r
\n" ); document.write( "\n" ); document.write( "sec^2x-csc^2x=(tan^2x + 1)-(1 +cot^2x \r
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\n" ); document.write( "\n" ); document.write( "=tan^2 x + 1-1 - cot^2 x\r
\n" ); document.write( "\n" ); document.write( "=tan^2x - cot^2x\r
\n" ); document.write( "\n" ); document.write( "=(tan x - cotx)(tan x + cotx)..................use identities tanx= sinx/cosx and cotx = cosx/sinx\r
\n" ); document.write( "\n" ); document.write( "=(tan x - cotx)(sin x/cos x +cos x/sin x)\r
\n" ); document.write( "\n" ); document.write( "=(tan x - cotx)((sin xsin x +cos xcos x)/sin xcos x\r
\n" ); document.write( "\n" ); document.write( "=(tan x - cotx)((sin ^2x +cos^2 x)/sin xcos x\r
\n" ); document.write( "\n" ); document.write( "=\"%28tan+x+-+cotx%29%281%2Fsin+xcos+x%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"%28tan+x+-+cotx%29%2Fsin+xcos+x\"\r
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