document.write( "Question 433514: The perimeter of a badminton court is 128 ft. After a game a badminton, a player's coach estimates that the athlete has run a total 444feet, which is equivalent to six times the courts length plus nine times it's width. What are the dimensions of a standard badminton court? \r
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Algebra.Com's Answer #300526 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
Perimeter=2Length+2Width
\n" ); document.write( "128=2L+2W
\n" ); document.write( "444=6L+9W
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\n" ); document.write( "6L+9W=444
\n" ); document.write( "6L+6W=384
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\n" ); document.write( "3W=60
\n" ); document.write( "W=20
\n" ); document.write( "L=44
\n" ); document.write( "The standard badminton court is 44'X 20'.
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Solved by pluggable solver: Linear System solver (using determinant)
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++2%5Cx+%2B+2%5Cy+=+128%2C%0D%0A++++6%5Cx+%2B+9%5Cy+=+444+%29%0D%0A++\"
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\n" ); document.write( " Any system of equations:
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\n" ); document.write( " (x=44, y=20}
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