document.write( "Question 433514: The perimeter of a badminton court is 128 ft. After a game a badminton, a player's coach estimates that the athlete has run a total 444feet, which is equivalent to six times the courts length plus nine times it's width. What are the dimensions of a standard badminton court? \r
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document.write( "Do not know how to start? \n" );
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Algebra.Com's Answer #300526 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! Perimeter=2Length+2Width \n" ); document.write( "128=2L+2W \n" ); document.write( "444=6L+9W \n" ); document.write( "---------------- \n" ); document.write( "6L+9W=444 \n" ); document.write( "6L+6W=384 \n" ); document.write( "---------------- \n" ); document.write( "3W=60 \n" ); document.write( "W=20 \n" ); document.write( "L=44 \n" ); document.write( "The standard badminton court is 44'X 20'. \n" ); document.write( "
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