document.write( "Question 433505: A store sells cashews for $5.00 per pound and peanuts for $2.00 per pound. The manager decides to mix 10 pounds of peanuts with some cashews and sell the mixture for $3.00 per pound. How many pounds of cashews should be mixed with the peanuts so that the mixture will produce the same revenue as would selling the nuts seperately? \n" ); document.write( "
Algebra.Com's Answer #300524 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! Let cashews equal x, peanuts y. Then: \n" ); document.write( "x + y=10 \n" ); document.write( "5x+2y=10*3=30 \n" ); document.write( "-------------- \n" ); document.write( "5x+2y=30 \n" ); document.write( "2x+2y=20 \n" ); document.write( "---------- \n" ); document.write( "3x=10 \n" ); document.write( "x=10/3 \n" ); document.write( "y=20/3 \n" ); document.write( "So, 10/3lbs. of cashews, 20/3lbs. of peanuts. \n" ); document.write( "
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