document.write( "Question 433505: A store sells cashews for $5.00 per pound and peanuts for $2.00 per pound. The manager decides to mix 10 pounds of peanuts with some cashews and sell the mixture for $3.00 per pound. How many pounds of cashews should be mixed with the peanuts so that the mixture will produce the same revenue as would selling the nuts seperately? \n" ); document.write( "
Algebra.Com's Answer #300524 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
Let cashews equal x, peanuts y. Then:
\n" ); document.write( "x + y=10
\n" ); document.write( "5x+2y=10*3=30
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\n" ); document.write( "5x+2y=30
\n" ); document.write( "2x+2y=20
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\n" ); document.write( "3x=10
\n" ); document.write( "x=10/3
\n" ); document.write( "y=20/3
\n" ); document.write( "So, 10/3lbs. of cashews, 20/3lbs. of peanuts.
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Solved by pluggable solver: Linear System solver (using determinant)
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+10%2C%0D%0A++++5%5Cx+%2B+2%5Cy+=+30+%29%0D%0A++\"
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\n" ); document.write( " Any system of equations:
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\n" ); document.write( " has solution
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\n" ); document.write( " (x=3.33333333333333, y=6.66666666666667}
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