document.write( "Question 433500: Solve: $\"+4%5Ex-2%5Ex-12=0+\"$ \n" ); document.write( "

Algebra.Com's Answer #300517 by belle3833(46) $\"\"$ $\"About$

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$\"+4%5Ex-2%5Ex-12=0+\"$
\n" ); document.write( "= $\"2%5E%282x%29-2%5Ex-12=0\"$
\n" ); document.write( "ley $\"y=2%5Ex\"$ \r
\n" ); document.write( "\n" ); document.write( "so we have:\r
\n" ); document.write( "\n" ); document.write( " $\"y%5E2-y-12=0\"$
\n" ); document.write( "= $\"%28y-4%29%28y%2B3%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( "y=4,y=-3\r
\n" ); document.write( "\n" ); document.write( "since $\"y=2%5Ex\"$
\n" ); document.write( "we need to solve $\"2%5Ex=4\"$ and $\"2%5Ex=-3\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"2%5Ex=-3\"$ has no solutions so we look at $\"2%5Ex=4\"$ . here x=2 \n" ); document.write( "

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