Algebra.Com's Answer #300480 by jorel1380(3719)  You can put this solution on YOUR website! x2-2x+3x-2+x+5+x+4=47 \n" );
document.write( "x2+3x+7=47 \n" );
document.write( "x2+3x-40=0 \n" );
document.write( "(x+8)(x-5)=0 \n" );
document.write( "x=-8,5 \n" );
document.write( "Throwing out the negative answer, we get x=5. \n" );
document.write( "The sides are 9,10,13,15. \n" );
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document.write( " | Solved by pluggable solver: SOLVE quadratic equation with variable | \n" );
document.write( "Quadratic equation (in our case ) has the following solutons: \n" );
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document.write( " For these solutions to exist, the discriminant should not be a negative number. \n" );
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document.write( " First, we need to compute the discriminant : . \n" );
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document.write( " Discriminant d=169 is greater than zero. That means that there are two solutions: . \n" );
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document.write( " Quadratic expression can be factored: \n" );
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document.write( " Again, the answer is: 5, -8.\n" );
document.write( "Here's your graph: \n" );
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