document.write( "Question 433452: Please help me with this difficult homework problem:\r
\n" ); document.write( "\n" ); document.write( "A company uses printer cartridges from three manufacturers. Manufacturers A, B, and C supply, respectively, 60%, 30%, and 10% of the company’s cartridges. 1% of cartridges from A, 2% from B, and 3% from C are defective. If a cartridge is randomly chosen and found to be defective, what is the probability that it is from manufacturer C?
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Algebra.Com's Answer #300477 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "conditional probability
\n" ); document.write( "given that the one you choose is defective then do the math\r
\n" ); document.write( "\n" ); document.write( "\"%28.02%2A.30%29%2F%28.01%2A.60%29%2B%28.02%2A.30%29%2B%28.03%2A.1%29\"\r
\n" ); document.write( "\n" ); document.write( "or is this bayes theroem? idk\r
\n" ); document.write( "\n" ); document.write( "\".006%2F.015+=+40\" %
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