document.write( "Question 433448: The height of a right triangle is 6 inches longer than the base. The area of the triangle is 108 sq in.
\n" ); document.write( "Find the measures of the triangles base and height. \n" ); document.write( "
Algebra.Com's Answer #300463 by nerdybill(7384)\"\" \"About 
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\n" ); document.write( "The height of a right triangle is 6 inches longer than the base. The area of the triangle is 108 sq in.
\n" ); document.write( "Find the measures of the triangles base and height.
\n" ); document.write( ".
\n" ); document.write( "Area of any triangle is:
\n" ); document.write( "(1/2)bh
\n" ); document.write( "where
\n" ); document.write( "b is base
\n" ); document.write( "h is height
\n" ); document.write( ".
\n" ); document.write( "so, now we have:
\n" ); document.write( "Let b = length of base
\n" ); document.write( "then
\n" ); document.write( "b+6 = length
\n" ); document.write( ".
\n" ); document.write( "So
\n" ); document.write( "(1/2)b(b+6) = 108
\n" ); document.write( "b(b+6) = 216
\n" ); document.write( "b^2+6b = 216
\n" ); document.write( "b^2+6b-216 = 0
\n" ); document.write( "(b+18)(b-12) = 0
\n" ); document.write( "b = {-18, 12}
\n" ); document.write( "We can throw out the negative solution leaving:
\n" ); document.write( "b = 12 inches (base)
\n" ); document.write( ".
\n" ); document.write( "Height:
\n" ); document.write( "b+6 = 12+6 = 18 inches\r
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