document.write( "Question 433400: Annual starting salaries for college graduates with business administration degrees are believed to have a standard deviation of approximately $2000. Assume that a 95% confidence interval estimate of the population mean annual starting salary is desired. How large a sample should be taken if the desired margin of error is\r
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document.write( " (a.) $500 ___________
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document.write( " (b.) $200 ___________
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document.write( " (c.) $100 ___________
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document.write( "
Algebra.Com's Answer #300430 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Annual starting salaries for college graduates with business administration degrees are believed to have a standard deviation of approximately $2000. Assume that a 95% confidence interval estimate of the population mean annual starting salary is desired. How large a sample should be taken if the desired margin of error is \n" ); document.write( "(a.) $500 ___________ \n" ); document.write( "(b.) $200 ___________ \n" ); document.write( "(c.) $100 ___________ \n" ); document.write( "---------------- \n" ); document.write( "n = [zs/E]^2 \n" ); document.write( "--- \n" ); document.write( "a) n = [1.96*2000/500]^2 = 7.84^2 = 62 when rounded up \n" ); document.write( "---- \n" ); document.write( "b) n = [1.96*2000/200]^2 = 19.6^2 = 385 when rounded up \n" ); document.write( "--- \n" ); document.write( "c) n = [1.96*2000/100]^2 = 39.2^2 = 1537 when rounded up\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |