document.write( "Question 433314: Nancy traveled 6 miles upstream to do some fly fishing. It took her 20 minutes longer to get there than to return. If the current in the river is 2 miles per hour, then how fast will her boat go in still water. \n" ); document.write( "
Algebra.Com's Answer #300386 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
To find Nancy's rate of travel, we have to solve for:
\n" ); document.write( "6/x-2=6/(x+2)+1/3hr.
\n" ); document.write( "Multiply both sides by 3(x-2)(x+2), we get:
\n" ); document.write( "18(x+2)=18(x-2)+x2-4
\n" ); document.write( "18x+36=18x-36+x2-4
\n" ); document.write( "0=x2-76
\n" ); document.write( "76=x2
\n" ); document.write( "√76=x
\n" ); document.write( "√4√19=x
\n" ); document.write( "2√19=x
\n" ); document.write( "-------------
\n" ); document.write( "Nancy's boat goes about 8.72 mph in still water.
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B0x%2B-76+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%280%29%5E2-4%2A1%2A-76=304\".
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\n" ); document.write( " Discriminant d=304 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-0%2B-sqrt%28+304+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%280%29%2Bsqrt%28+304+%29%29%2F2%5C1+=+8.71779788708135\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%280%29-sqrt%28+304+%29%29%2F2%5C1+=+-8.71779788708135\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B0x%2B-76\" can be factored:
\n" ); document.write( " \"1x%5E2%2B0x%2B-76+=+1%28x-8.71779788708135%29%2A%28x--8.71779788708135%29\"
\n" ); document.write( " Again, the answer is: 8.71779788708135, -8.71779788708135.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B0%2Ax%2B-76+%29\"
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